kotlin 二进制_Kotlin程序将十进制转换为二进制

kotlin 二进制

We are given a decimal number and we will create a Kotlin program to convert decimal number to binary.

我们给了十进制数，我们将创建一个Kotlin程序将十进制数转换为二进制 。

To convert decimal number to binary, we will recursively divide the decimal number by 2 and save the remainder found till the decimal number vanquishes.

要将十进制数转换为二进制，我们将十进制数递归除以2，然后将找到的余数保存到十进制数消失。

Example:

例：

    Input:
    Decimal number = 12

    Recursive division:

Number	Quotient	Remainder
12	6	0
6	3	0
3	1	1
1	0	1

Output: Here, we will read the remainders in reverse order which is the binary equivalent i.e.

数	商	余
12	6	0
6	3	0
3	1个	1个
1个	0	1个

输出：在这里，我们将以相反的顺序读取余数，即二进制等效项，即 1100 is the binary conversion for 1100是 12. 12的二进制转换。

在Kotlin中将十进制转换为二进制的程序 (Program to convert decimal to binary in Kotlin)

package com.includehelp.basic

import java.util.*

/* function to convert given decimal number into Binary */
fun getBinaryNumber(decimalNumber: Int): String {
    var decimalNumber = decimalNumber
    val binaryStr = StringBuilder()
    
    while (decimalNumber > 0) {
        val r = decimalNumber % 2
        decimalNumber /= 2
        binaryStr.append(r)
    }
    
    return binaryStr.reverse().toString()
}

// Main Method Entry Point of Program
fun main(arg: Array<String>) {
    val sc = Scanner(System.`in`)
    
    println("Enter Decimal Number  : ")
    //Input Decimal Number
    val decimalNumber: Int = sc.nextInt()
    
    // Call function to Convert Decimal into binary
    val binaryNumber = getBinaryNumber(decimalNumber)
    // Print Binary Number
    println("Binary Number : $binaryNumber")
}

Output

输出量

Run 1:
Enter Decimal Number  :
15
Binary Number : 1111
-----
Run 2:
Enter Decimal Number  :
12345
Binary Number : 11000000111001
----
Run 3:
Enter Decimal Number  :
545654
Binary Number : 10000101001101110110