python">#思路：利用ord方法将遍历后的字符串值转化为ASCLL,并于ASCLL表对比即可
def count(str):
    symbol = 0
    number = 0
    letter = 0
    blank = 0
    for i in str:
        if 33 <= ord(i) <= 47 or 58 <= ord(i) <= 64 or 91 <= ord(i) <= 96 or 123 <= ord(i) <= 126:
            symbol += 1
        elif 48 <= ord(i) <= 57:
            number += 1
        elif 65 <= ord(i) <=90 or 97 <= ord(i) <= 122:
            letter += 1
        elif ord(i) == 32:
            blank += 1
    print(f'字符串里大小写字母个数为：{letter} 数字个数为{number} 符号个数为：{symbol} 空格个数为：{blank}' )
str = input("请输入您想要识别个数的字符串\n")
count(str)